The product A in the following reaction is:CH | vedclass

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(C) The reaction of a nitrile $(-CN)$ with $DIBAL-H$ (Diisobutylaluminium hydride) at $-78^{\circ}C$ followed by acid hydrolysis $(H_3O^+)$ is a selec

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$CH_3-CH=CH-CH_2-CHO$

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(C) The reaction of a nitrile $(-CN)$ with $DIBAL-H$ (Diisobutylaluminium hydride) at $-78^{\circ}C$ followed by acid hydrolysis $(H_3O^+)$ is a selective reduction method to produce an aldehyde.$DIBAL-H$ reduces the nitrile group to an imine intermediate,which upon hydrolysis yields the corresponding aldehyde.Crucially,$DIBAL-H$ does not reduce the carbon-carbon double bond $(C=C)$ present in the molecule.Therefore,the reaction is:$CH_3-CH=CH-CH_2-CN \xrightarrow[(2) H_3O^+]{(1) DIBAL-H, -78^{\circ}C} CH_3-CH=CH-CH_2-CHO$The correct product $A$ is $CH_3-CH=CH-CH_2-CHO$.

The product $A$ in the following reaction is:
$CH_3-CH=CH-CH_2-CN \xrightarrow[(2) H_3O^+]{(1) DIBAL-H, -78^{\circ}C} A$

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The product $A$ in the following reaction is:$CH_3-CH=CH-CH_2-CN \xrightarrow[(2) H_3O^+]{(1) DIBAL-H, -78^{\circ}C} A$